What is the starting mass of ethyl acetoacetate if the Density is 1.029 g/cm3 and the volume is 3.0mL?
The correct answer and explanation is :
To calculate the mass of ethyl acetoacetate, we can use the formula that relates density, mass, and volume:
[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
]
From this, we can rearrange the equation to solve for mass:
[
\text{Mass} = \text{Density} \times \text{Volume}
]
Given:
- Density of ethyl acetoacetate = 1.029 g/cm³
- Volume = 3.0 mL
Step 1: Convert the volume to cubic centimeters (cm³)
Since 1 mL is equivalent to 1 cm³, the volume of 3.0 mL is the same as 3.0 cm³.
Step 2: Calculate the mass
Using the formula for mass:
[
\text{Mass} = 1.029 \, \text{g/cm}^3 \times 3.0 \, \text{cm}^3
]
[
\text{Mass} = 3.087 \, \text{grams}
]
Final Answer:
The starting mass of ethyl acetoacetate is 3.087 grams.
Explanation:
The relationship between density, mass, and volume is foundational in many areas of chemistry and physics. Density is a physical property that indicates how much mass is contained within a specific volume of a substance. In this case, the density of ethyl acetoacetate is given as 1.029 g/cm³, which means that each cubic centimeter (cm³) of ethyl acetoacetate weighs 1.029 grams.
To find the mass of a given volume of a substance, you multiply the density by the volume. In this problem, the volume of ethyl acetoacetate is 3.0 mL, and since 1 mL equals 1 cm³, the volume is also 3.0 cm³.
Multiplying the density (1.029 g/cm³) by the volume (3.0 cm³) gives a result of 3.087 grams. This tells us that the total mass of the 3.0 mL of ethyl acetoacetate is 3.087 grams.
This type of calculation is commonly used when working with liquid substances in chemistry labs to determine the amount of material in a given sample, and it also highlights the importance of understanding the relationship between density and mass.