Draw the best Lewis structure for CH2F2

Draw the best Lewis structure for CH2F2. Which of the following is/are true? Select all that apply.

CHF2 is nonpolar
There are dispersion forces between two CH2F2 molecules
There are dipole-dipole forces between two CH2F2 molecules
There is hydrogen bonding between two CH2F2 molecules
The strongest intermolecular force between two CH2F2 molecules is ion-dipole forces
CHF2 should have a lower boiling point than CH4
The molecular geometry for CH2F2 is tetrahedral

The correct answer and explanation is :

To analyze CH₂F₂ (difluoromethane), let’s first draw its Lewis structure and evaluate its properties.

Lewis Structure of CH₂F₂:

Carbon (C) is the central atom:

Carbon forms 4 single bonds: 2 with H atoms, and 2 with F atoms.
Each H has 1 bond (full shell).
Each F has 3 lone pairs (6 electrons) and 1 bond to C.

So, the structure looks like:

    H
    |
F - C - F
    |
    H

Molecular Geometry:

Using VSEPR theory, CH₂F₂ has 4 bonding regions and no lone pairs on carbon, resulting in a tetrahedral geometry.

Polarity:

Fluorine is much more electronegative than hydrogen, so the C–F bonds are strongly polar.
The molecule is not symmetrical because the F atoms are not evenly distributed around the carbon.
Dipoles do not cancel out, so CH₂F₂ is polar.

Intermolecular Forces:

Dispersion forces: Always present in all molecules.
Dipole-dipole forces: Present due to polarity.
Hydrogen bonding: Requires H bonded to N, O, or F within the same molecule, which CH₂F₂ lacks. So, no hydrogen bonding between molecules.
Ion-dipole forces: Occur between ions and polar molecules—not applicable here since CH₂F₂ is neutral.

Boiling Point Comparison (CH₂F₂ vs CH₄):

CH₄ (methane) is nonpolar, has only dispersion forces, and a very low boiling point (−161°C).
CH₂F₂ is polar with dipole-dipole interactions → higher boiling point than CH₄.

✅ Correct Statements:

✅ There are dispersion forces between two CH₂F₂ molecules.
✅ There are dipole-dipole forces between two CH₂F₂ molecules.
✅ The molecular geometry for CH₂F₂ is tetrahedral.

❌ Incorrect Statements:

❌ CHF₂ is nonpolar → CH₂F₂ is polar.
❌ There is hydrogen bonding → No H bonded to O/N/F in this context.
❌ Strongest force is ion-dipole → No ions present.
❌ CHF₂ has lower boiling point than CH₄ → CH₂F₂ has a higher boiling point.