Harriet earns the same amount of money each day

Harriet earns the same amount of money each day. Her gross pay at the end of 7 workdays is 35h+56 dollars. Which expression represents her gross pay each day?

The Correct and E xplanation is:

To find Harriet’s gross pay each day, we are given that her total gross pay for 7 workdays is:

$$
35h + 56 \text{ dollars}
$$

Step 1: Understand What We’re Solving

We want to find how much Harriet earns in one day, given that her total for 7 days is $35h + 56$. Since she earns the same amount each day, we can divide the total by 7.

Step 2: Divide the Expression by 7

We divide the entire expression $35h + 56$ by 7:

$$
\frac{35h + 56}{7}
$$

To simplify:

  • Divide each term in the numerator by 7: $$
    \frac{35h}{7} + \frac{56}{7} = 5h + 8
    $$

✅ Final Answer:

$$
\boxed{5h + 8}
$$


📘 Explanation (300+ Words):

This is an algebraic problem involving division of a polynomial by a constant. We’re told that Harriet earns a fixed amount of money each day, and her total pay for 7 days is represented by the expression $35h + 56$. The goal is to find her daily earnings, which involves finding an expression that, when multiplied by 7, gives $35h + 56$.

To do this, we apply the distributive property of division over addition. This property allows us to divide each term in a sum separately. So instead of trying to simplify the entire expression at once, we break it down:

$$
\frac{35h + 56}{7} = \frac{35h}{7} + \frac{56}{7}
$$

  • First, divide $35h$ by 7: $$
    \frac{35h}{7} = 5h
    $$
  • Next, divide 56 by 7: $$
    \frac{56}{7} = 8
    $$

Now, combine the two results:

$$
5h + 8
$$

This simplified expression tells us that each day, Harriet earns an amount equal to 5 times some hourly rate $h$, plus 8 extra dollars. This could represent, for example, a base fee or bonus included daily.

Using algebra in this way helps break down complex earnings over multiple days into a simple, manageable form. This is useful for budgeting, payroll, and understanding financial patterns.

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