A dosage chart recommends 15 mg of amoxicillin (common antibiotic) for every 2.2 lbs of a dog’s weight. Mr. Joe, Ms Jill’s dog, weighs in at a whopping 125 pounds. What is the proper dose, in mg, for Mr. Joe?
The Correct Answer and Explanation is:
Correct Answer: 852.27 mg
Step-by-Step Explanation:
We are given a dosage ratio and the weight of the dog:
- Dosage recommendation: 15 mg of amoxicillin for every 2.2 lbs of body weight.
- Mr. Joe’s weight: 125 pounds
Step 1: Understand the relationship
The dosage recommendation is a proportion, meaning for every 2.2 pounds, the dog receives 15 mg of medication. This can be expressed as a unit rate: Dosage per pound=15 mg2.2 lbs≈6.8182 mg per pound\text{Dosage per pound} = \frac{15\ \text{mg}}{2.2\ \text{lbs}} \approx 6.8182\ \text{mg per pound}
Step 2: Multiply by the dog’s weight
Now we multiply the unit dosage by Mr. Joe’s weight: Proper dosage=6.8182 mg/lb×125 lbs=852.27 mg\text{Proper dosage} = 6.8182\ \text{mg/lb} \times 125\ \text{lbs} = 852.27\ \text{mg}
So, Mr. Joe should receive approximately 852.27 mg of amoxicillin.
Step 3: Why this matters
This calculation demonstrates how proportional reasoning is essential in medication dosing, especially in veterinary or pediatric care, where dosages are often based on weight. Giving too little of a drug can be ineffective in treating an infection, while giving too much can be dangerous or even toxic.
Because amoxicillin is a powerful antibiotic, accuracy is important to ensure the infection is treated without causing harm. Overdosing could lead to side effects such as gastrointestinal upset or allergic reactions. Underdosing, on the other hand, might fail to eliminate the infection and could contribute to antibiotic resistance.
Conclusion
By using a simple ratio and converting the weight into a dosage using multiplication, we found that a 125-pound dog like Mr. Joe needs 852.27 mg of amoxicillin. This kind of calculation is a vital part of safe and effective medication administration in both veterinary and human medicine.